I have a simple filter that takes input based upon the url. urlpatterns = patterns('ahrlty.listings.views', (r'^(?P<listing_type>.*)$', 'index'), )
In the view I do a simple validation against a tuple in my listings model that I use for choices in a field. if dict(Listing.listing_types).has_key(listing_type) == False: listing_type = None And finally I get my data filtering on the listing_type if it exists, otherwise I just want all the data. (Instead of none of it.) if listing_type: data = Listing.objects.filter(is_published = True, listing_type = listing_type) else: data = Listing.objects.filter(is_published = True) That last if statement works for this situation but I can see a situation where I'm passing a few optional arguments in and an if statement would get unwieldy. I was thinking of chaining the filters for each optional field. data = Listing.objects.filter(is_published = True) if listing_type: data = data.filter(listing_type = listing_type) Is there a better way to construct the filter? -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.