On Apr 3, 3:31 pm, Imuvy <ivan.marches...@gmail.com> wrote: > Dear Django Users > I'm new to django and I'm creating my first django application. > I'm using the development version > > I was able to create a model and automatically create a form using > modelform > > My model contains a lot of table/class but I'm going to create the > form only by means of on table/class > this is part of the model: > > ______________________________________ > > class TipoIndagine(models.Model): > cod_tipo = models.IntegerField(primary_key=True) > desc_tipo = models.CharField(max_length=100) > cod_classe = models.ForeignKey(ClasseIndagine, > db_column='cod_classe') > class Meta: > db_table = u'tipo_indagine' > > class Indagine(models.Model): > cod_indagine = models.AutoField(primary_key=True) > #cod_indagine = models.IntegerField(IndaginiSpatial, > db_column='cod_indagine') > cod_tipo = models.ForeignKey(TipoIndagine, db_column='cod_tipo') > data = models.DateField() > ditta = models.CharField(max_length=100) > cod_falda = models.ForeignKey(Falda, db_column='cod_falda') > cod_comune = models.ForeignKey(Comune, db_column='cod_comune') > localita = models.CharField(max_length=100) > quota_pc = models.DecimalField(max_digits=8, decimal_places=3) > usosuolo = models.CharField(max_length=100) > note = models.CharField(max_length=100) > cod_pratica = models.ForeignKey(Pratica, db_column='cod_pratica') > compilatore = models.CharField(max_length=100) > nome_indag = models.CharField(max_length=100) > the_geom = models.PointField() > objects = models.GeoManager() > def __unicode__(self): > return self.cod_tipo > #return u'%s' % self.cod_tipo > class Meta: > db_table = u'indagine' > ___________________________________ > > This is the simple form code: > _______________________________ > class IndagineForm(ModelForm): > class Meta: > model = Indagine > _______________________________ > > The form is loading but the foreignkey fields only show a drop down > list containing a lot of "nameOfClass object" > > I have read this > posthttp://groups.google.com/group/django-users/browse_thread/thread/02ad... > And I put into the Indagine class these rows: > def __unicode__(self): > return self.cod_tipo > > but the __unicode__ method seems not to solve the problem. > > Now, using __unicode__ method as shown above, when I load my > models.Indagine into the python shell and I call the class, I obtain: > > >>> from geotec_db.models import Indagine > >>> Indagine.objects.all() > > Traceback (most recent call last): > File "<console>", line 1, in <module> > File "/usr/lib/python2.6/dist-packages/django/db/models/query.py", > line 69, in __repr__ > return repr(data) > File "/usr/lib/python2.6/dist-packages/django/db/models/base.py", > line 345, in __repr__ > u = unicode(self) > File "/home/ivan/geotecdb_django/../geotecdb_django/geotec_db/ > models.py", line 92, in __unicode__ > return u'%s' % self.cod_tipo > File "/usr/lib/python2.6/dist-packages/django/db/models/fields/ > related.py", line 264, in __get__ > raise self.field.rel.to.DoesNotExist > DoesNotExist > > I can't understand where is the problem... > > Please help me :-) > > Ivan
That method should have gone in the TipoIndagine model. -- DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
