On Mon, Mar 15, 2010 at 11:28 PM, saxon75 <saxo...@gmail.com> wrote: > I'm trying to generate a link where the URL of the current page gets > passed in the querystring of the link. Like so: <a href="http:// > www.example.com?variable=http%3A%2F%2Fwww.example2.com%2Farg1%2Farg2%2F"></a>. > > I would have thought that I could do this relatively easily with > template tags, so I've tried this: > > <% url arg1, arg2 as the_url %> > <a href="http://www.example.com?variable={{ the_url|urlencode }}"></a> > > However, for whatever reason, the urlencode filter isn't applied when > the_url renders. Is there a way to do this directly in the template, > or do I have to generate the encoded URL in the view and pass it to > the template?
Are you sure it's no applied? urlencode uses python's urllib.quote (http://docs.python.org/library/urllib.html#urllib.quote) and I think it doesn't encode the '/' character by default - maybe that's why you don't see any changes by applying the filter. Nuno -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
