*I know that I should serve static files using a static file server that was built for doing such, but save me the lecture and indulge me on this please*
I am serving large video files (180+MB) through HttpResponse in Django, and returning the file iteratively using Django's FileWrapper: http://code.djangoproject.com/browser/django/trunk/django/core/servers/basehttp.py#L32 I need to prepend some data on that video file before I return the file to the user, but I don't know how to do that without reading the entire file into memory using .read(). Is there any way I could extend FileWrapper to allow me to add data at the very beginning of the file, while it's allowing the video file to be read in chunks? Here is a simple example of what I am doing (my code has too much other crap going on, so I wrote this): import urllib2 from django.http import HttpResponse from django.core.servers.basehttp import FileWrapper def huge_video_view(request): response_handle = urllib2.urlopen('http://example.com/ hugeassvideo.flv') return HttpResponse(FileWrapper(response_handle), mimetype='video/ x-flv') Thanks, Brandon -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
