In the model's meta class, give it a field app_label, eg:
class MyModel(models.Model):
...
class Meta:
app_label = "myapp"
I use this to split my models into multiple files in a models
subdirectory of my app. Adding a __init__.py with
from modelfile import *
for each model file makes this directory into a models submodule.
On Feb 12, 2:49 am, Bill Freeman <ke1g...@gmail.com> wrote:
> One issue is that for syncdb to work it has to find all of the models.
> It does this,
> IIUC, by importing models from each INSTALLED_APP. If you can arrange for
> that to import your added model, you are on the right track. For example, you
> can make your models.py files each import an extra file containing the extra
> model(s) *for that app*. But I suspect that you are trying to do this without
> modifying the models.py files of the apps, and I don't see a simple approach,
> and complicated approaches (such as iterating through INSTALLED_APPS
> yourself and plugging an extra class into each in django's internal
> structures)
> is likely to be hard to maintain, and be dependent on django internals that
> can
> change from version to version.
>
> Bill
>
>
>
> On Thu, Feb 11, 2010 at 3:51 AM, Sameer Rahmani <lxsam...@gmail.com> wrote:
> > Hi ,
> > is there any way to build a new model from outside of models.py ? or in
> > other application ?
>
> > i want to build a model for a class for each application
>
> > --
> > lxsameer
>
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