D'oh! I must have clicked "reply to author" (I'm so used to hitting "reply to all" in Gmail).
I discovered a post which gives an example of Itay's suggestion in action: http://yuji.wordpress.com/2009/09/12/django-python-dynamically-create-queries-from-a-string-and-the-or-operator/. I also found this section of Python's documentation useful: http://docs.python.org/tutorial/controlflow.html#keyword-arguments. Thanks for your replies. Sorry for being slow on the uptake. I am relatively new to Python and didn't realize that it's possible to pass a dictionary to a function in place of arguments. Cool! On Feb 5, 2:25 am, Itay Donenhirsch <i...@bazoo.org> wrote: > i don't see any way for a python function to _require_ a parameter to > be hardcoded. > i would be VERY surprised otherwise. this must work... > i agree about python being designed awesomely though! :) > > On Thu, Feb 4, 2010 at 3:13 PM, davidchambers > > <david.chambers...@gmail.com> wrote: > > Thanks for the suggestion. Unless I'm mistaken, though, using a > > dictionary does not solve the problem which is that .filter() seems to > > require field names to be hard-coded. Django is incredibly well > > designed, though, and continually surprises me, so I'm almost > > _expecting_ to be pleasantly surprised here. :) > > > On Feb 5, 12:23 am, Itay Donenhirsch <i...@bazoo.org> wrote: > >> i guess you can do it with a dictionary, i'll give you a general example: > > >> def foo(x,y,z): > >> print "x=" + x > >> print "y=" + y > >> print "z=" + z > > >> d = { 'x' : 1, 'y': 2, 'z' : 3 } > >> foo( **d ) # same as foo( x=1, y=2, z=3 ) > > >> it's a python thing, not django necessarily > > >> On Thu, Feb 4, 2010 at 1:20 PM, davidchambers > > >> <david.chambers...@gmail.com> wrote: > >> > I'm familiar with hard-coding filters in the standard fashion, e.g. > >> > posts = Post.objects.filter(title__contains='django'). > > >> > I'm interested in finding out whether it's possible to replace > >> > title__contains in the above example with a variable. Why do I want to > >> > do this? Well, here's some pseudocode: > > >> > posts = Post.objects.all() > >> > if title checkbox is checked: > >> > posts = posts.filter(title__contains='django') > >> > if subheading checkbox is checked: > >> > posts = posts.filter(subheading__contains='django') > >> > if body checkbox is checked: > >> > posts = posts.filter(body__contains='django') > > >> > I would love to be able to do this with a loop: > > >> > posts = Post.objects.all() > >> > for field in ['title', 'subheading', 'body']: > >> > posts = posts.filter(field__contains='django') > > >> > Clearly the above will not work, but is there a way to achieve the > >> > result I'm after? > > >> > -- > >> > You received this message because you are subscribed to the Google > >> > Groups "Django users" group. > >> > To post to this group, send email to django-us...@googlegroups.com. > >> > To unsubscribe from this group, send email to > >> > django-users+unsubscr...@googlegroups.com. > >> > For more options, visit this group > >> > athttp://groups.google.com/group/django-users?hl=en. > > > -- > > You received this message because you are subscribed to the Google Groups > > "Django users" group. > > To post to this group, send email to django-us...@googlegroups.com. > > To unsubscribe from this group, send email to > > django-users+unsubscr...@googlegroups.com. > > For more options, visit this group > > athttp://groups.google.com/group/django-users?hl=en. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
