On Jan 12, 4:11 am, Tomasz Zieliński
<tomasz.zielin...@pyconsultant.eu> wrote:
> On 11 Sty, 16:23, Marco Rogers <marco.rog...@gmail.com> wrote:
>
> > I'm reposting this from earlier to see if I have better luck. I need
> > to be able to get the ModelAdmin associated with a model at runtime.
> > Similar to how django.db.models.get_model allows you to retrieve a
> > model.
>
> > admin_class = get_admin(Model)
>
> > Is this possible?
>
> > The original post has more info.
>
> >http://groups.google.com/group/django-users/browse_thread/thread/0cd0...
>
> Maybe something like this:
>
> 1. Write something like django.contrib.admin.autodiscover, to get all
> ModelAdmins
> 2. Iterate those ModelAdmins, retrieve models they are attached to and
> store this mapping in a dict.
> 3. def get_admin(model):
> return admin_to_model[model]
You should be able to iterate through admin.site._registry, and pull
out the one you need.
from django.contrib import admin
def get_admin(model):
for k,v in admin.site._registry.iteritems():
if v is model:
return v
Written in a browser.
Matt.
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-us...@googlegroups.com.
To unsubscribe from this group, send email to
django-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en.
