You do understand that when running under Apache that the code runs as
a special Apache user.
So, not only would the home directory not even be that for your home
account, Apache scrubs the HOME user environment variable from the
process environment anyway, and so trying to access HOME variable will
fail.
General rule in web programming is, never to rely on user environment
variables and secondly never rely on current working directory being a
particular location nor use relative paths, always use absolute paths
instead.
Graham
On Dec 10, 5:19 am, edward9 <edward...@gmail.com> wrote:
> Hello everybody
>
> I'm new and i want to say Hello to Everybody.
>
> I have problem with Apache. I install python, django, apache,
> mod_apache and all what is necessary.
>
> Apache configuration is:
> <Location "/mysite/">
> SetHandler python-program
> PythonHandler django.core.handlers.modpython
> SetEnv DJANGO_SETTINGS_MODULE mysite.settings
> PythonOption django.root /mysite
> PythonDebug Off
> #PythonPath "['/', '/mysite', '/var/www'] + sys.path"
> PythonPath "['/'] + sys.path"
> </Location>
>
> I created an application i root folder:
> django-admin.py startproject mysite
> and i started development(runserver). All works fine. "Configurations
> on your first Django-powered page". Running on apache also works fine.
>
> But when i create Django app:
> manage.py startapp inet
> views.py:
> # Create your views here.
> from django.http import HttpResponse
> from django.db import connection
> from django.conf import settings
> from datetime import datetime
>
> def main_page(request):
> output = '''
> <html>
> <head><title>%s</title></head>
> <body>
> <h1>%s</h1><p>%s</p><h2>%s</h2>
> </body>
> </html>
> ''' % (
> '1','a','b','c'
> )
> return HttpResponse(output)
>
> urls.py
> from django.conf.urls.defaults import *
> from inet.views import *
>
> urlpatterns = patterns('',
> (r'^$',main_page),
> )
>
> on development server works fine but started on apache i get:
>
> KeyError at /
>
> 'HOME'
>
> Request Method: GET
> Request URL: http://127.0.0.1/
> Exception Type: KeyError
> Exception Value:
>
> 'HOME'
>
> Exception Location: /usr/lib/python2.5/UserDict.py in __getitem__,
> line 22
> Python Executable: /usr/bin/python
> Python Version: 2.5.4
> Python Path: ['/', '/usr/lib/python2.5', '/usr/lib/python2.5/plat-
> linux2', '/usr/lib/python2.5/lib-tk', '/usr/lib/python2.5/lib-
> dynload', '/usr/local/lib/python2.5/site-packages', '/usr/lib/
> python2.5/site-packages', '/usr/lib/python2.5/site-packages/PIL', '/
> usr/lib/python2.5/site-packages/gst-0.10', '/usr/lib/pymodules/
> python2.5', '/usr/lib/python2.5/site-packages/gtk-2.0', '/usr/lib/
> pymodules/python2.5/gtk-2.0']
> Server time: Wed, 9 Dec 2009 11:54:14 -0600
> Traceback Switch to copy-and-paste view
>
> * /usr/lib/pymodules/python2.5/django/core/handlers/base.py in
> get_response
> 70.
> 71. # Get urlconf from request object, if available. Otherwise
> use default.
> 72. urlconf = getattr(request, "urlconf",
> settings.ROOT_URLCONF)
> 73.
> 74. resolver = urlresolvers.RegexURLResolver(r'^/', urlconf)
> 75. try:
> 76. callback, callback_args, callback_kwargs = resolver.resolve
> (
> 77. request.path_info) ...
> 78.
> 79. # Apply view middleware
> 80. for middleware_method in self._view_middleware:
> 81. response = middleware_method(request, callback,
> callback_args, callback_kwargs)
> 82. if response:
> 83. return response
> ▶ Local vars
> Variable Value
> exc_info
> (<type 'exceptions.KeyError'>, KeyError('HOME',), <traceback
> object at 0x932c57c>)
>
> Can somebody help me? I dont have any ideas how to solve this problem.
>
> Thnask for help!
> Regards
> Edward9
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-us...@googlegroups.com.
To unsubscribe from this group, send email to
django-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en.
