On Nov 20, 3:26 pm, JHeasly <jhea...@earthlink.net> wrote:
> In using Simon W.'s "simple example of row-level permissions in the
> admin" (http://www.djangosnippets.org/snippets/1054/), I'm trying to
> extend the concept by modifying the 'list_filter' tuple of the
> subclassed ModelAdmin based upon the request.user.is_superuser
> property buy am struggling with how to hook it into my class.
>
> Intuitively, it seems like overriding the __init__ ModelAdmin is where
> it needs to go. I've tried something like:
>
> def __init__(self, model, admin_site, request, *args, **kwargs):
> if request:
> if request.user.is_superuser:
> self.list_filter = ('has_run',)
> super(Death_noticeAdmin, self).__init__(model, admin_site,
> request, *args, **kwargs)
>
> but the above fouls the registering of the Death_noticeAdmin class:
>
> File "/usr/local/lib/python2.5/site-packages/django/contrib/admin/
> sites.py", line 93, in register
> self._registry[model] = admin_class(model, self)
>
> TypeError: __init__() takes at least 4 arguments (3 given)
>
> My lack of a completely thorough understanding of 'super' probably
> isn't helping either. Any suggestions, ideas appreciated.
>
> — J.
Basically you don't want to pass the 'request' argument up the super
class, as it isn't expecting it. Use the **kwargs magic instead.
def __init__(self, model, admin_site, *args, **kwargs):
request = kwargs.pop('request', None)
if request:
if request.user.is_superuser:
self.list_filter = ('has_run',)
super(Death_noticeAdmin, self).__init__(model, admin_site,
*args, **kwargs)
--
DR.
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