> if not cleaned.has_key("string2") and > cleaned.has_key("string1"): > cleaned["string2"] = string1 > > return cleaned > I think the problem here is that if string2 is not required it will be in the cleaned dictionary but an empty string. So instead you might need:
if not cleaned.get('string2', ''): cleaned['string2'] = string1 I'd still suggest doing it like this though, not in the POST, as you would need to do that in every view where you use the form. Peter -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=.