or create a function that return object.foreign_key.field1. then use the function in list_display
cheers. -djibon- On 10/14/09, justquick <justqu...@gmail.com> wrote: > > try using 'foreign_key__field1' instead > > On Oct 14, 12:04 pm, freeav8r <freea...@yahoo.com> wrote: >> Is it possible to do something like this: >> >> class MyModelAdmin(admin.ModelAdmin): >> list_display = (‘field1’, field2’, ‘foreign_key’, >> ‘foreign_key.field1’, foreign_key.field2’,) >> >> admin.site.register(MyModel, MyModelAdmin) >> >> ‘foreign_key’ works just fine, but ‘foreign_key.field1’ and >> ‘foreign_key.field2’ error out. Any suggestions? > > > -- -------------------------------------------------------------- http://www.tumbletooth.org my linkedin profile : http://www.linkedin.com/in/bayuadji -------------------------------------------------------------- --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
