Is there some trick to parse
http://www.example.com/foo/42
such that "42" becomes an integer parameter to the view function,
instead of a string?
Right now I have to do:
from my.app.views import foo
urlpatterns = patterns('',
(r'foo/(?P<bar_str>\d+)/?$' , foo),
)
my/app/views.py
def foo(request, bar_str):
bar = int(bar_str)
This is obviously not so convenient. It would be much nicer to simply
have the pattern auto-converted to an integer. I understand the
Python reasons for why it works this way, but if there were some
Django shortcut to help with this, that would be great.
Ian
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