On Sep 6, 8:39 am, Joshua Partogi <joshua.part...@gmail.com> wrote:
> Dear all,
>
> I have a model that has a foreign e.g
>
> class Foo(models.Model):
> bar = models.ForeignKey(Bar)
>
> class Bar(models.Model):
> name = models.CharField(max_length=50)
>
> This is my FooAdmin:
> class FooAdmin(admin.ModelAdmin):
> list_display = ['bar']
>
> Now in the admin Foo's display list I want to have a link to go to bar
> display list. What would be the best way to do that in django? I tried to
> search in the doc but could not find a relevant howto on this issue.
>
> Thanks in advance for the insights.
>
> regards,
>
Define a custom method on the FooAdmin class which returns the HTML of
a link to the Bar changelist with the relevant filter applied:
def bar_link(self, obj):
return '<a href="/admin/myapp/bar/?foo=%s">See Bars</a>' %
obj.pk
bar_link.allow_tags = True
See
http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display
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