Hello, My project is Web-based and I work in Django environment on Linux. Let me give a Scenario first.
A user whose username is "peter" logins into "www.myfoo.com" online. After his username/password get authenticated, he arrives this webpage "www.myfoo.com/user_login". On this page it looks like this. Welcome Peter (1.) Go to my profile (2.) Check my total credit points (3.) .... (1.), (2.), (3), etc, are all links. If peter clicks one of them, then he will be redirected to a new webpage. For example, if he clicks (1.), then he will be transferred to webpage "www.myfoo.com/peter/ profile/". For this webpage there is a def (or module) "user_profile (request)" in View. This module needs to get this URI (or at least "/ peter/profile/) and parse it so that peter's profile can be retrieved from a database. Now my question is: how can the module "user_profile(request)" get "peter"? Or, how can the module get the URI? os.environ[...] does not work here as this is not cgi. request.user is not good either as it gives in-exact result. Any ideas and suggestions? Thanks so much. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
