If you look here http://docs.djangoproject.com/en/dev/topics/db/models/#id7 you'll see that multi-table inheritance is handled at the db level "via an automatically-created OneToOneField". This means that an instance of B has a foreign key to an instance of A.
At the model level, there should be an a_ptr and an a_ptr_id attributes (check with a dir(b) for example). The first one is the instance of A associated with b, and the second the id of that instance of A. So, I imagine that: b = B() b.a_ptr = a b.save() or b = B() b.a_ptr_id = a_id b.save() should do what you want. Rodrigue On Jul 20, 4:03 pm, Peter Cicman <pcic...@gmail.com> wrote: > Hi, i didn't found noting about it in docs, so i'll try to ask, first > explanation, i have: > > class A(models.Model): > name = models.CharFiled(...., required=True) > ..... > > class B(A): > .... > > I have an existing instance of A, say `a` > > and i "want to make" instance of b out of it. > > i'm looking for something like: > b = B() > b.origin = a > b.save() > > Is this somehow possible? > > Thanks a lot! --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
