Whilst I appreciate that hidden fields can be less than ideal in some
cases I want to set default values in a form generated from a model.

http://code.djangoproject.com/wiki/CookBookManipulatorWithHiddenFields
gives some guidance but this approach appears to be deprecated in
django 1.02 (and the refernced cookbook pages does not say so)

What is the new way to do this pls?

Thx.  Paul

class Note(models.Model):
  organisation = models.ForeignKey(Organisation)
  contact = models.ForeignKey(Contact)
  last_contact = models.DateTimeField()
  notes = models.TextField(blank=True)
  def __str__(self):
    return '%s %s' %(self.last_contact,self.contact)

class NoteForm (ModelForm):
  class Meta:
    model=Note

###### deprecated #######
class NoteManipulator(Note.AddManipulator):
  def __init__(self):
    # Set everything up initially using the built in manipulator
    Note.AddManipulator.__init__(self)
    newFields = []
    # replacing some fields with HiddenFields
    for field in self.fields:
      if field.field_name in ('user',):
         field = formfields.HiddenField(field.field_name,
           field.is_required,
           field.validator_list)
      newFields.append(field)
    self.fields = newFields

def note(request,id=''):
  if request.method == "POST":
  .. processing stuff here ..
  else:
    oid=request.GET.get('oid','')
    if  id:
      # prepare for update
      inst=Note.objects.get(id=id)
      form=NoteForm(instance=inst)
      submit="Update"
    else:
     # prepare for insert
      # default foreign key on new record
      manipulator = noteManipulator()
      dflt={'organisation=oid': oid}
      errors={}
      ### deprecated
      form=NoteForm().FormWrapper(manipulator, dflt, errors)
      submit="Insert"
    return render_to_response('crm/note.html',{
      'form': form,
      'id': id,
      'oid': oid,
      'submit': submit,
    })
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