HI Eric,
thanks for the reply.
I sort of found a solution, by poking through the contrib.syndication
app, I added this function to my model:
from django.template import loader
def render(self):
html_tmp = loader.get_template(self.html_template_name)
html = loader.render_to_string(html_tmp.name, {'obj': self})
return html
where self.html_template_name is the path + name of the template, and
it's passed the calling model instance as 'obj'.
Thanks!
Rodrigo
On May 19, 11:50 pm, Eric Abrahamsen <gir...@gmail.com> wrote:
> On May 20, 2009, at 10:53 AM, Roberto Cea wrote:
>
>
>
> > I have a large amount of optional components (with a model for each
> > one) that will be freely inserted by my users, and it would be
> > impractical to render each one in a single large template.
> > I want to give each component a ".render()" method, so I can just call
> > that from the template.
> > However, I don't want to have to put together each component's HTML in
> > its model definition. Ideally, each component would have a
> > corresponding template file, that would be added together with the
> > page's other components' output to generate the complete page's HTML.
> > Is there a way to specify, for each model, a small template-snippet
> > file that will be used to represent it? Hopefully using Django
> > standard template syntax?
>
> I'm not sure this will completely solve your problem, but in several
> cases I've added python-only (non-database) attributes to models,
> pointing at a template in my template dirs directory. That way you can
> use generic code to render snippets for a variety of different models.
> You could create a mixin class that provides the render() method,
> using django's template rendering functions and a reference to
> self.component_template, then have models subclass this mixin and
> provide their own component_template attribute.
>
> Hope that's what you were looking for.
>
> Eric
>
>
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