On Fri, 2009-04-10 at 18:15 -0700, chris wrote:
>
>
> On Apr 10, 6:55 pm, Malcolm Tredinnick <malc...@pointy-stick.com>
> wrote:
>
> > However there could be, and likely are, many TextChar objects with the
> > same edition value, so it would be ambiguous as to which particular
> > object to return. Since there's no natural choice, there's no API to ask
> > Django to guess or provide a sample object or anything like that. It's
> > not appropriate to return a model object for that type of query.
> >
> > What is the real problem you are trying to solve here? Why do you need
> > an object back?
>
> Well, I want to display in a template the name of the edition, rather
> than the primary key, which means nothing to the user. Meanwhile I
> resorted to do the footwork in the view function like so, which allows
> me to achieve what I need:
>
> reslist = [{'edition' :Edition.objects.get(pk=a['edition']).__unicode__
> (), 'count': a['char__count']} for a in char.textchar_set.values
> ('edition').annotate(Count('char'))]
Aah .. I'm dumb. I misread your original question as asking for a
TextChar object back (since you were querying on the TextChar model).
Returning Edition models -- which is indeed what you were asking for and
since completing my remedial reading course I can now see that -- is
definitely possible. Use Edition as the root for the queryset (the model
to query). This does what you're after:
Edition.objects.filter(textchar__unichar=char).annotate(Count("textchar"))
That will return a bunch of Edition objects, each with a textchar__count
attribute.
Sorry for being so dense early on.
Regards,
Malcolm
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