On Mon, Mar 9, 2009 at 11:21 PM, Rama Vadakattu <ramaakrish...@gmail.com>wrote:
>
> I have a list in template.
> I need to access that list based on a forloop.counter.
>
> For example :
>
> if forloop.counter is 1 then i need to access list[1]
> if forloop.counter is 5 then i need to access list[5]
> .
> so on..........
>
> I tried below techniques to solve the above problem.but none of them
> is working.
> Any hint on how to do this?
>
> 1. {% for k in klist %}
>
> {{ mylist.forloop.counter }} #This code is not
> working
> {% endfor %}
>
>
> 2. {% for k in klist %}
>
> {{% with forloop.counter as xl %}
> {{mylist.x }} #This code is not working
> {% endwith %}
>
> { %endfor %}
>
> 3. {% for k in klist %}
> {{ mylist|slice:forloop.counter:forloop.counter }} #This
> code is not working
> { %endfor %}
>
> Regards
> Rama vadakattu
>
>
>
>
>
>
>
>
>
>
> >
>
is there a reason you can't just do {{ k }} why would an item be at a
different position then it's index?
Alex
--
"I disapprove of what you say, but I will defend to the death your right to
say it." --Voltaire
"The people's good is the highest law."--Cicero
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to
django-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
