use two underscores to address the other table/model institution_institution
vs institution__institution django querysets rock ! On Tue, Mar 3, 2009 at 10:19 PM, Jesse <adles...@gmail.com> wrote: > > I tried that option and received this error: > > Cannot resolve keyword 'institution_institution' into field > > However, I think I may have it. I used this statement: > > qset2 = ( > Q(institution__icontains=queryr) > ) > resultsi = Institution.objects.filter(qset2).distinct() > for id in resultsi: > resultsii=Researchproject.objects.filter(institution=id) > > And am able to get the results in the template. It just makes for > more coding, however, in the view. It would be easier to have all the > code in the qset and not have to add another qset2. > > On Mar 3, 1:01 pm, Tim <timster...@gmail.com> wrote: > > If you want to look up an Institution using the Project model, you > > should be able to use "institution__institution__icontains" > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
