Ajax would only be necessary if you want a status bar that reflects
accurately the progress. You can probably get by with something
simpler. I would write some Javascript that is triggered on clicking
the submit button that replaces the button with this graphic:
http://yesmagazine.org/store/images/pleasewait.gif


Your Javascript looks like this:

?>
<script language="javascript" type="text/javascript"><!--


function SubmitOrderButton(){
        document.getElementById("submitmain").style.display = "none";

        if (navigator.appName == "Microsoft Internet Explorer") {
        document.getElementById("pleasewait").innerHTML = "";
        document.getElementById("pleasewait").style.display = "block";
        document.getElementById("pleasewait").innerHTML = "<img src='images/
pleasewait.gif' alt='Please Wait'>";
        } else {
        document.getElementById("pleasewait").style.display = "block";
        }
}

//--></script>

And your HTML code looks like this:

<div id="submitmain" class="buttonRow forward">
        <input type="submit" name="btn_submit" value="Confirm Order"
class="checkout_button"  />
</div>
<div id="pleasewait" class="buttonRow forward" style="display:none">
        <img src="/images/pleasewait.gif"><br />
       Please wait while your request is being processed...
</div>

Cheers,
Kevin Audleman

On Feb 18, 2:52 pm, Malcolm Tredinnick <malc...@pointy-stick.com>
wrote:
> On Wed, 2009-02-18 at 12:20 +0000, Adam Stein wrote:
> > Maybe somebody can suggest how to get the functionality I'm trying to
> > duplicate.  I looked and can't find anything that seemed similiar.
>
> > I have a form with checkboxes.  User selects one or more and submits the
> > form.  The processing currently goes like this:
>
> > 1) Write JavaScript to display moving progress bar
> > 2) Process based on checked boxes (which in my specific example is to
> > copy the specified databases into a sandbox area)
> > 3) Write JavaScript to turn off progress bar
>
> > The database copying is short, up to about 20 seconds.  Short enough to
> > let the user wait, long enough that I want to indicate the computer
> > hasn't frozen :-{}
>
> > It seems that I can only return HTML to be displayed once from a view.
> > Is there a way to get the functionality described above somehow?
>
> It's called AJAX. You have to keep asking the server for an update and
> then updating the page.
>
> Regards,
> Malcolm
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to 
django-users+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to