thanks for your reply
On Feb 13, 2:46 pm, Rama Vadakattu <ramaakrish...@gmail.com> wrote: > there are many ways of solving this problem. > please see the below thread for more details where similar problem was > discussed > :http://groups.google.com/group/django-users/browse_thread/thread/3a99... > > Another method which you can use is > ==================================== > for respective model override the save as follows > > class Model(): > > #this code syntax may not be proper > def save(self): > super(self) #at this point it will save and you will know the id > self.account_number = "X"+self.id > self.save() > > The syntax may be wrong as i have did not do it earlier > The core idea is to override the save and then call its parent to save > the object,after saving using that object id form account number > and save it again > > On Feb 13, 12:54 pm, gganesh <ganesh....@gmail.com> wrote: > > > hello , > > i will be glad to find your help in the task mentioned below , > > i need to create a account_number column which is a concat of id > > column and with some variable ,for example, if my id column is 1 ( id > > =1) and account_number should be X1(account_number=X1) and if my id is > > 2 the account_number must be X2 and so on > > thanks --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
