On Jan 23, 1:39 am, Julien Phalip <jpha...@gmail.com> wrote:
> I have a view which processes a multi-part form and whose behaviour
> varies depending on the content types of the uploaded files. I've
> written some tests for that view as follows:
>
> post_data = {
> 'name1': 'blah',
> 'file_field1': image_data,
> }
> response = self.client.post('/upload/', post_data)
>
> But the problem is that (apparently by design) all files are
> systematically encoded with the content type 'application/octet-
> stream'.
>
> Is there a more concise or more elegant way to do?
>
The UploadedFile[1] object has a field called content_type. So if you
have this in a form:
myfile = request.FILES['some_file']
if myfile.content_type != 'application/zip':
#raise error
I don't know if this will help you in your test. I hope it does.
[1]
http://docs.djangoproject.com/en/dev/topics/http/file-uploads/#uploadedfile-objects
John
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