On 9 jan, 17:06, "burcu hamamcıoğlu" <borco...@gmail.com> wrote:
> Hi everybody,
>
> do you know how can i get request url in views.py.
>
> My url pattern is like (r'^wp/rmain2\.aspx','DisplayPacketApplications2'),
> But my link is like :http://wap2.cepoyun.com/wp/rmain2.aspx?pid=194&w=280jhjh
>
> when i use 'PATH_INFO' i olnly get 'wp/rmain2\.aspx' of the link. How can i
> get the full link above ?
request.get_full_path() will give you the path + the querystring.
http://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.get_full_path
But if what you want is to get the 'pid' and 'w' arguments of the
querystring, it might be simpler to use request.GET, ie:
def youview(request):
pid = request.GET.get(pid)
w = request.GET.get(w)
# you code here
Have a look at the FineManuel(tm) for more about the HttpRequest
object:
http://docs.djangoproject.com/en/dev/ref/request-response/
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