On Sun, 2008-11-30 at 03:14 -0200, Felipe Sodré Silva wrote: > Hello folks. I have three models:
[...] > I know that this is going to generate three different tables. > I want to know if is it possible to do: > > cars = Car.objects.all() > for c in cars: > ..print c.render() > > and get the expected result, without having to check the actual type > of each car. That depends on your definition of "expected result". Since you're iterating over a queryset of Car objects, you'll get back a Car object each time. That's a fairly natural expectation. However, if you are guessing that you'll get back the most-derived object (Porsche, etc), then no that won't happen, since it requires information that isn't possible to encode into a single SQL query with what Django has available at the moment it makes the query. Regards, Malcolm --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
