Hi Alex, > Here is the code that I use. Output_list is from CVS and current_projects > is from the database. Is there a faster way to do this, or a built in > method in Python? This code works fine now, but I can see it getting slow. > > for b in output_list: > found = False > for i in current_projects: > if i.name == b: > found = True > if not found: > new_projects.append(b)
Try converting the two project name lists into Python sets and take a difference: full_list = set(output_list) db_list = set([i.name for i in current_projects]) new_projects = full_list - db_list You should also add a unique=True attribute to your project.name field. -Rajesh D --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
