Thanks for the answer Malcolm.
Maybe I was unclear where I put the line "related_contacts =
Contact.objects.filter(projects_involved__title__startswith=title)".
Sorry for that.
It was in the "Project" model, not in a view. When I validate the code
as follows I get the described error no matter if I use starts_with or
startswith.
class Contact(models.Model):
projects_involved = models.ManyToManyField('Project', blank=True)
class Project(models.Model):
title = models.CharField(max_length=100)
related_contacts = Contact.objects.filter
(projects_involved__title__startswith=title)
client = models.ManyToManyField(Contact,
related_name='client',blank=True, limit_choices_to=related_contacts)
collaborators = models.ManyToManyField
(Contact,related_name='collaborators', blank=True,
limit_choices_to=related_contacts)
Now I already see a second problem myself. In the docs it says
"limit_choices_to has no effect when used on a ManyToManyField with an
intermediate table". So my choices list would have no effect if it
worked.
Maybe you could give me some general advice on how to approach what I
had mind.
Thanks - Silvan
On Nov 20, 2:10 am, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Wed, 2008-11-19 at 13:35 -0800, Silvano wrote:
> > Dear all
>
> > I'm completely stuck with the following problem.
>
> > What I'm trying to accomplish is: I have an app with the model
> > "Project" and another model "Contacts". In "Contacts" I have a m2m
> > field called "projects_involved" relating to the "Project" model which
> > allows to select projects the contact is involved with.
> > In my "Project" model I have some m2m fields like "client" and
> > "collaborators" where I want to store a relation to some of the
> > contacts. In the admin interface the user should be provided with
> > contacts related to the actual "Project" only.
>
> > class Contact(models.Model):
> > projects_involved = models.ManyToManyField('Project', blank=True)
>
> > class Project(models.Model):
> > title = models.CharField(max_length=100)
> > client = models.ManyToManyField(Contact, related_name='client',
> > blank=True)
> > collaborators = models.ManyToManyField(Contact,
> > related_name='collaborators', blank=True)
>
> > What I tried so far is to use a filter for constructing a choices list
> > within the “Project” model.
>
> > related_contacts = Contact.objects.filter
> > (projects_involved__title__starts_with=title)
>
> But that isn't really what you have in your view. The lookup type in
> Django is "startswith" (no underscore). If you wrote the above, it would
> complain that "title" is not a joinable field.
>
> > This gives me the following error in
> > "/django/db/models/fields/__init__.py" line 102, in __cmp__
> > return cmp(self.creation_counter, other.creation_counter)
> > AttributeError: 'str' object has no attribute 'creation_counter'
>
> That error message is normally related to model creation, not filtering.
> So what happens when you run "manage.py validate"? I suspect it will
> report that same error. In which case, you've left something out of your
> example code, because when I cut-and-paste exactly what you've written,
> I don't see that error.
>
> So run "manage.py validate" and make sure the same error is reported.
> Then look at your code carefully to work out what is different between
> what you have and what you've pasted here (start by pasting exactly what
> you have here into a new project and verify it doesn't raise an error;
> then slowly build up to what you have in the case that is causing the
> error).
>
> Regards,
> Malcolm
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