Got it fixed. I was making mistake -)
On Nov 20, 12:22 pm, laspal <[EMAIL PROTECTED]> wrote:
> OK I got the point but still having some problem dealing with excel
> file.
>
> code:
> abspath = '/home/laspal/work/test/tmp/'
> ********* view***************
> if not os.path.isdir(abspath + str(_user.username)):
> os.mkdir(abspath + str(_user.username) )
> filepathwithname = os.path.join(abspath + str
> (_user.username), file_name)
> if not os.path.isfile(filepathwithname):
> workbook.save(os.path.join(abspath + str(_user.username),
> file_name))
>
> cronemail = CronEmail()
> filecontent = ContentFile(filepathwithname)
>
> cronemail.attach.save(filepathwithname, filecontent)
>
> if os.path.isfile(filepathwithname):
> os.remove(os.path.join(abspath + str(_user.username),
> file_name))
> if os.path.isdir(abspath + str(_user.username)):
> os.removedirs(abspath + str(_user.username))
>
> The problem I am facing is the excel file is getting save but not able
> to get content of excel file.
> Or is there any other way of handing it? I know I am saving the same
> file twice.
>
> Thanks
> On Nov 18, 8:24 pm, Rajesh Dhawan <[EMAIL PROTECTED]> wrote:
>
> > laspalwrote:
> > > Hi,
> > > I am trying to savefileusingfilefieldbut ran into problem.
> > > Here is my code:
>
> > > ***********model************
>
> > > class CronEmail(models.Model):
> > > subject = models.CharField( max_length = 200)
> > > message = models.CharField( max_length = 200)
> > > sender = models.CharField( max_length = 200)
> > > send_to = models.CharField(max_length = 200)
> > > attach = models.FileField(upload_to='example', null = True)
> > > created_on = models.DateTimeField(auto_now_add=True)
> > > updated_on = models.DateTimeField( auto_now = True)
>
> > > ****************form******************
> > > class SendMailForm(forms.Form):
> > > attach = forms.FileField(required= False)
> > > subject = models.CharField( max_length = 200)
> > > message = models.CharField( max_length = 200)
> > > sender = models.CharField( max_length = 200)
> > > send_to = models.CharField(max_length = 200)
>
> > > ****************settings.py********
> > > MEDIA_ROOT = os.path.join('/home/laspal/work/test/', 'static/media')
> > > MEDIA_URL = '/static/media/'
>
> > > *******view**************
>
> > > emailform = SendMailForms(request.POST, request.FILES)
> > > ........
> > > cronemail = CronEmail()
> > > attach = request.FILES['attach']
> > > cronemail.subject = subject
> > > and so on
> > > cronemail.save()
>
> > > So my problem how can I save attachfilewith the other info in
> > > cronemail.
> > > I tried cronemail.save_attach_fiel( filename, filecontent) but it
> > > gives me error.
>
> > Try:
>
> > cronemail.attach.save(filename, filecontent)
>
> > Where, filecontent is an instance of django.core.files.File. If your
> > filecontent is request.FILES['attach'], just use it directly as it's
> > an instance of UploadedFile which . If it's raw content, wrap it in
> > afileobject before calling the save method above:
>
> Ok I got the point but still I am having problem
>
> > from django.core.files.base import ContentFile
> > filecontent = ContentFile(raw_content)
>
> > If you continue getting errors, please post the error trace along with
> > the your code as it helps people provide more direct answers.
>
> > > So can some one help me out in savingfile.
> > > and also I wanted to know how can I get the storedfileand delete
> > > it?
>
> > cronemail.attach.delete()
>
> > -Rajesh Dok
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