This is actually worse
blog/models.py
----------------
from django.shortcuts import render_to_response as RenderToResponse
from myblog.blog.models import Post
def listposts(request):
a = Post.objects.all()
a = list(a)
a[0].title = 'hihi'
a[0].content = 'haha'
return RenderToResponse('blog/showlist.html',{'postlist': a});
Just shows me a blank page (with <h1>Hello</h1> on top).
What am I missing?
On Oct 22, 8:17 am, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Tue, 2008-10-21 at 22:30 -0700, guruyaya wrote:
>
> [...]
>
> > blog/views.py
> > -----------
> > from django.shortcuts import render_to_response as RenderToResponse
> > from myblog.blog.models import Post
> > def listposts(request):
> > a = Post.objects.all()
> > a[0].title = 'hihi'
> > a[0].content = 'haha'
> > print a[0].title
> > print a[0].content
> > return RenderToResponse('blog/showlist.html',{'postlist': a});
>
> [...]
>
> > As you may have guest, I expected the first post title to be 'hihi'
> > and it's content to be 'haha'. Well... it's not. I still get the same
> > post I have in my database. Yet the "print" lines give me the right
> > post content in the server debug messages.
>
> That's because a[0] is not updating 'a' in place. Instead, it's
> returning a new queryset, that contains a slice of the original one and
> then that clone is updated. You are still passing the original 'a' to
> the template, however.
>
> If you want to do updating in place, you'll need to convert 'a' to an
> object that supports those types of updates, namely a list:
>
> a = list(a)
> a[0].title = 'Now updated in place because a is a list!'
>
> Realise that this isn't the sort of thing that is normally going to be a
> problem because it's just not that normal a usage pattern. Typically,
> you will either be extracting a bunch of data in a queryset and passing
> that to a template, *or* you will be iterating through a queryset or
> getting one particular object, updating the object(s) and then saving
> them. Not mixing both at once.
>
> Regards,
> Malcolm
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