hi, I know this is probably easy, but ...
I have a category model: class Category(models.Model): name = models.CharField(max_length=100, unique=True) slug = models.SlugField(max_length=100, unique=True) parent = models.ForeignKey('self',blank=True,null=True) ... the view function that browses categories should return a list of sub- categories based on receiving the slug field of the parent value. however, the parent is set to the id value, not the slug. How do I associate the parent with the parents slug? my view currently looks like this: def category(request, myslug): category_list = get_list_or_404(Category, parent=myslug) return render_to_response('listings/browse.html', {'category_list': category_list}) this expects the parents id in myslug, I obviously need the parents slug. any help appreciated, thanks. (using django 1.0) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---