You can't really do it that easily with the default django template
language,
bu check out Jinnja2,
http://jinja.pocoo.org/2/documentation/
it's an alternative template language/system that can be plugged into
django.

it offers what you need and more useful features that save you time
and make you more productive.
its syntax is very similar to django (infact it was inspired by
django)

On Oct 7, 2:43 pm, Kasper Grubbe <[EMAIL PROTECTED]> wrote:
> Hi again.
>
> In my application i need to know if a number in a list is bigger than
> 1000 or got 4 letters in it. I have to do this in my template.
>
> This is my code in the template:
> <ul class="menu-list">
> {% for menuitem in availList %}
>       {% if menuitem|length > 3 %}
>             <b>{{ menuitem }}</b>
>       {% else %}
>             {{ menuitem }}
>       {% endif %}
> {% endfor %}
> </ul>
>
> Is there any thing i can do to achieve this?
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at 
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to