Hi everyone,
I have a view to do some re-ordering of a list via ajax:
@staff_member_required
def reorder(request):
collections = Collection.objects.all()
if request.method == 'POST':
pk_ids = request.POST['pk_ids'].split(',')
length = len(pk_ids)
for collection in collections:
for i in xrange(length):
id = pk_ids[i]
if str(collection.id) == str(id):
collection.position = (i + 1)
collection.save()
return render_to_response('empty.html')
else:
return render_to_response('admin/portfolio/collection/
reorder.html', {'collections' : collections})
When I call "reorder" via ajax and post data, Django complains if I
don't return an HttpResponse object. So, I've just been returning an
empty html file. Is there a more elegant way to handle this?
TIA,
Brandon
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
