It can be achieved using a Search model, but only if you only need search on a single model.
class YourModel(models.Model): ... clsss Search(models.Model): yourmodels = models.ManyToManyField(YourModel) So the search form is POST not GET. After POST'ing, you do the searching, then create a new Search object, store the results into it's yourmodels field, and save it. Next you'll need a search results view which takes a search ID. That view only needs to do Search.objects.get(pk=search_id).yourmodels.all() to get the results (or yourmodels.all()[m, n] if you're doing pagination. This way you'll have short URL's for search results (like /search/8293/). If you need to search across multiple models, I'd consider django- search or similar. Erik On 29.09.2008, at 5:12, Brandon Taylor wrote: > > Hi everyone, > > I have a search results page and need to be able to go to a detail > page for any result. I would like to provide the user a way to return > to their search results and not clutter the querystring with search > parameters. > > What's the best approach for this using Django? Should I stuff the > queryset into a session? > > TIA, > Brandon > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
