Hello
I'm making a small app that holds data of servers in our organisation
(the database existed previously, and I've created the models.py using
the inspectdb as described in:
http://docs.djangoproject.com/en/dev/howto/legacy-databases/ )
The admin site works OK, but each server is displayed as "Server
object". I would like the admin site to display each item under its
servername. How can I do that?
part of the models.py:
class Server(models.Model):
id = models.IntegerField(primary_key=True)
servername = models.CharField(max_length=192)
ip = models.CharField(max_length=48)
domainname = models.CharField(max_length=96, blank=True)
os = models.CharField(max_length=96, blank=True)
drives = models.CharField(max_length=24, blank=True)
backedupto = models.CharField(max_length=192, blank=True)
purpose = models.CharField(max_length=384, blank=True)
comment = models.CharField(max_length=768, blank=True)
siteid = models.IntegerField(null=True, blank=True)
authid = models.IntegerField(null=True, blank=True)
class Meta:
db_table = u'server'
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