Karthik Krishnan wrote:
> The stack trace is given below
> 
> Traceback (most recent call last):
>   File "manage.py", line 11, in <module>
>     execute_manager(settings)
>   File "c:\tools\Python25\Lib\site-packages\django\core\management
> \__init__.py",
>  line 340, in execute_manager
>     utility.execute()
>   File "c:\tools\Python25\Lib\site-packages\django\core\management
> \__init__.py",
>  line 295, in execute
>     self.fetch_command(subcommand).run_from_argv(self.argv)
>   File "c:\tools\Python25\Lib\site-packages\django\core\management
> \base.py", lin
> e 77, in run_from_argv
>     self.execute(*args, **options.__dict__)
>   File "c:\tools\Python25\Lib\site-packages\django\core\management
> \base.py", lin
> e 87, in execute
>     translation.activate('en-us')
>   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> \__init__.py
> ", line 73, in activate
>     return real_activate(language)
>   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> \__init__.py
> ", line 43, in delayed_loader
>     return g['real_%s' % caller](*args, **kwargs)
>   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> \trans_real.
> py", line 209, in activate
>     _active[currentThread()] = translation(language)
>   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> \trans_real.
> py", line 198, in translation
>     default_translation = _fetch(settings.LANGUAGE_CODE)
>   File "c:\tools\Python25\Lib\site-packages\django\utils\translation
> \trans_real.
> py", line 181, in _fetch
>     app = getattr(__import__(appname[:p], {}, {}, [appname[p+1:]]),
> appname[p+1:
> ])
>   File "c:\tools\Python25\Lib\site-packages\django\contrib\admin
> \__init__.py", l
> ine 1, in <module>
>     from django.contrib.admin.options import ModelAdmin, HORIZONTAL,
> VERTICAL
>   File "c:\tools\Python25\Lib\site-packages\django\contrib\admin
> \options.py", li
> ne 5, in <module>
>     from django.contrib.contenttypes.models import ContentType
>   File "c:\tools\Python25\Lib\site-packages\django\contrib\contenttypes
> \models.p
> y", line 1, in <module>
>     from django.db import models
>   File "c:\tools\Python25\Lib\site-packages\django\db\models
> \__init__.py", line
> 5, in <module>
>     from django.db.models.query import Q
>   File "c:\tools\Python25\Lib\site-packages\django\db\models
> \query.py", line 7,
> in <module>
>     from django.db.models.fields import DateField
>   File "C:\tools\Python25\lib\site-packages\django\db\models\fields
> \__init__.py"
> , line 666
>     class DecimalField(max_digits = 32, decimal_places =
> 0)IntegerField(Field):
>                                   ^
> SyntaxError: invalid syntax
> 
> The stack trace does not define which line has an incorrect syntax. I
> am having this error even there is nothing in the models.py file.

It says it happened on line 666 of 
C:\tools\Python25\lib\site-packages\django\db\models\fields\__init__.py 
just at the equals sign "max_digits = 32".

-- 
Norman J. Harman Jr.
Senior Web Specialist, Austin American-Statesman
___________________________________________________________________________
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