You could try the template filter "unordered_list" too I believe (haven't done it myself).
http://docs.djangoproject.com/en/dev/ref/templates/builtins/#unordered-list Cheers On Sep 11, 11:36 am, "Lance F. Squire" <[EMAIL PROTECTED]> wrote: > Currently using Django version 0.96.3, on a Fedora 8 system. > > I've currently set-up models for 'Manufacturer' and 'System'. System > has a Foreignkey to Manufacturer. > > I'd like to display a list like so: > > Manu A > System a > System b > System c > > Manu B > System a > System b > System c > > Etc... > > Only listing Manufacturers that had systems of type X. > > I was thinking of using code like this in the View, > > man=Manufacturer.objects.all()>>> for m in man: > > ... sys=System.objects.filter(manufacturer=m.id) > ... print m.name > ... for s in sys: > ... print " %s" % s.name > ... > > This works from the shell, but I'm unsure how to get the output to the > template And, I suspect is a terribly inefficient way to do it anyway. > > I'm guessing I should be doing something simpler here and then doing > something in the template to form the list.... > > Any help appreciated, including severe beatings with a clue stick. ;) > > This is only my 2nd attempt at a Django project, and I'm stumped at > the moment. > > Thanks, > > Lance --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
