Dear Ivan, your help is priceless, thanks!
Ivan Sagalaev wrote:
[...]
> In models.py you can get rid of repeating "Manufacturer" two extra times
> by doing:
>
> class Manufacturer(models.Model):
> name = models.CharField(max_length=30)
> address = models.CharField(max_length=50)
>
> admin.site.register(Manufacturer, admin.ModelAdmin)
> Also you can register admins for all models in a loop:
Done, it works great.
> > Isn't there sort of a wildcard or shortcut to catch all those
> > cases at once?
>
> You can make one yourself through some python-fu:
>
> (r'(?P<model>\w+)/?$', model_view(list_detail.object_list)),
> (r'^(?P<model>\w+)/(?P<object_id>\d+)/?$',
> model_view(list_detail.object_detail)),
> (r'^(?P<model>\w+)/create/?$', model_view(create_object)),
> (r'^(?P<model>\w+)/update/(?P<object_id>\d+)/?$',
> model_view(update_object)),
>
> "Model_view" here is a decorator that would take model name from
> argument and turn it into a respective queryset:
>
> # mapping from lowercased names of models to models
> from django.db.models import Model
> import models
> model_classes = dict(
> (i.__class__.__name__.lower(), i)
> for i in dir(models)
> if isinstance(i, Model)
> )
>
> def model_view(func):
> def wrapper(request, *args, **kwargs):
> model = kwargs.pop('model')
> kwargs['queryset'] = model_classes[model].objects.all()
> return func(request, *args, **kwargs)
> return wrapper
This is the urls.py I created: http://dpaste.com/72138/
It doesn't work though: I get a
KeyError at /manufacturer
u'manufacturer'
when accessing http://localhost:8000/manufacturer
(manufacturer being one of my model)
Thank you very much for any further help,
Fabio.
--
fabio natali
http://poisson.phc.unipi.it/~natali
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