On Jun 15, 1:58 pm, "./ed" <[EMAIL PROTECTED]> wrote:
> ## forms.py
> class aForm(forms.Form):
> choicelist = [(obj.id,obj.myfield) for obj in
> aModel.objects.all()]
> mod = forms.ChoiceField(choice=choicelist)
>
> that's not exactly the code because the choice list is computed in
> another python file.
>
> the problem is that when i add an entry to the aModel table it does
> not update in the form (even with various reload scheme)
> it does update when I 'touch' the python file. So my guess is the
> problem lies in the 'compilation' chain or something like that.
>
> As anyone an idea how I can fix this problem because I can't allow
> users to 'touch' the python files
>
> Thanks
>
> ./ed
What's happening is that in your code, Django is working out the
options at compile time. To make them dynamic, put the code in the
__init__ method of the form - that way they'll be computed each time
the form is instantiated.
However, you may find that an easier option is to use a
ModelChoiceField rather than a basic ChoiceField:
def myForm(forms.Form):
mod = ModelChoiceField(aModel.objects.all())
See http://www.djangoproject.com/documentation/newforms/#modelchoicefield
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DR.
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