Just to throw in another variable. The recursion comes from file
django/db/models.py in method get_follow:
def get_follow(self, override=None):
follow = {}
for f in self.fields + self.many_to_many +
self.get_all_related_objects():
if override and f.name in override:
child_override = override[f.name]
else:
child_override = None
fol = f.get_follow(child_override)
if fol != None:
follow[f.name] = fol
return follow
The same issue was reported in this ticket
http://code.djangoproject.com/ticket/3288
and said to be fixed in this changeset
http://code.djangoproject.com/changeset/7477#file19
Please if someone can throw some insight? Really appreciate your help.
Cliff
On Jun 7, 6:28 pm, Cliff <[EMAIL PROTECTED]> wrote:
> Hi,
> This is the simplified version of my code:
> class Test(models.Model):
> parent = models.ForeignKey('self',edit_inline=models.TABULAR)
>
> and the error I got:
> RuntimeError: maximum recursion depth exceeded
>
> I can understand that's because it's doing recursive for the child
> object, grand child object and so on until it reaches the upper limit
> of recursion. What I really want to do is just one level of recursion,
> so I get a structure of the following if know what I mean:
> test(parent)
> --test1(child)
> --test2(child)
> --test3(child)
>
> Is there a way to achieve this?
> Thanks
> Cliff
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