Hi all, I have a ForeignKey object (designset) as part of a model class and can get the project value associated with foreignkey object using...
def project(self): project = self.designset.project return project I can then use this created field in the list_display options for the admin site - great! but when I try and use in the list_filter I get the error: FieldDoesNotExist Compound has no field named 'project' This is fair enough but is there a cunning way to get this foreignkey value passed into the filters menu???? Thanks - any help greatly appreciated! Martin --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---