Concider this:
parent = models.ForeignKey('self', null=True, blank=True,
related_name='children')So my user makes a database that has root level1 level2 level3 If the user moves level1 under level3 than the database breaks and I get this error. ProgrammingError: (2014,, "Commands out of sync; you can't run this command now") This is because the chain is broken where each level point to its parent up to root! How can I avoid this in the admin! --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
