example: http://127.0.0.1:8000/search/?q=keyword
"request.path" can just get "/search/" How can I get "/search/?q=keyword " ? ================================================ My current solution: In my view: full_path = request.path + '?' + request.META['QUERY_STRING'] In my template: <a href="/accounts/login/?next={{ full_path }}">Sign in</a> It worked, but I think it's not a good way. ================================================ Is there a better way to do this? Just like: <a href="/accounts/login/?next={{ request.what }}">Sign in</a> --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---