Django Code wrote:
> #7101: ordering ForeignKey(self) =FieldError: Infinite loop caused by
> ordering.
> -----------------------------------------------------+----------------------
> Reporter: Carl Karsten <[EMAIL PROTECTED]> | Owner:
> nobody
> Status: closed | Component:
> Core framework
> Version: SVN | Resolution:
> invalid
> Keywords: | Stage:
> Unreviewed
> Has_patch: 0 | Needs_docs:
> 0
> Needs_tests: 0 | Needs_better_patch:
> 0
> -----------------------------------------------------+----------------------
> Changes (by mtredinnick):
>
> * status: new => closed
> * needs_better_patch: => 0
> * resolution: => invalid
> * needs_tests: => 0
> * needs_docs: => 0
>
> Comment:
>
> That code was already broken, but you just hadn't noticed. Django is now
> correctly reporting the error. If you order by the parent, then the
> parents should be order by their parents and so on. Since that's
> impossible to encode in SQL, previous versions of Django were returning
> only a single level of ordering, which was very inconsistent.
>
> Either remove the infinite loop or use `order_by('parent_id')` if you want
> a workaround to simulate the previous ambiguous behaviour.
>
order_by('parent_id') doesn't do anything for the Admin UI, which is where I
'need' this. I can probably live without it, but the previous behavior grouped
siblings (child with same parent) together, and put the 'root nodes' (no
parent)
at the top. This was handy.
I can now kinda get this behavior by using the list_filter = ('parent',) but so
far I am finding that awkward.
I think the nature of a site's menu is such that the previous was useful, but I
can see that it wouldn't make any sense for a larger dataset.
So, anyone have any suggestions on how to create something similar?
Carl K
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