I don't know how to do this in Python, if you even can. Inspect may be just the dark scary corner to explore to find this capability if it exists. But why would you want to do something like this? Even if inspect could do this, it looks like called would have to have some very specific knowledge of caller's structure to make it work.
Much much better would be to get caller and called to cooperate, and have called simply return a value that caller would check. Or for the two to be based on a template pattern (template as in the Gang of Four book, not as in a Django template). Maybe if you told us a bit more about the problem, we could help you find a solution. --Ned. http://nedbatchelder.com/blog Julien wrote: > Hi all, > > This is more a Python issue than a Django one, but I thought the > Python-aware people that you are might be able to help me :) > > I would like to do something like: > > def called(arg) > if arg==True: > !!magic!!caller.return 1 > > def caller(arg) > called(arg) > return 2 > > Here, the fake !!!magic!!! represents a statement (which I ignore) > that would make the caller function return a value different from what > it'd return normally. > > For example, caller(True) would return 1, and caller(False) would > return 2. The reason I want that is because I don't want the caller > function to know what's going on in the called function, and be > shortcut if the called function think it's necessary. > > Would you know if that's possible, and if so, how? > > I've done a bit of research and I think I've found some good pointers, > in particular using the 'inspect' library: > > import inspect > > def called(arg) > if arg==True: > caller_frame = inspect.stack()[1] > ... > > Here 'caller_frame' contains the frame of the caller function. Now, > how can I make that frame return a particular value? > > Hope that was clear... :/ > > Thanks! > > Julien > > > > -- Ned Batchelder, http://nedbatchelder.com --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
