ah so the idea is to us a url something like this
for form
/module/item_id/edit
and save to
/module/item_id/save
feels queer but i'll try and get used to it. thanks i guess i
couldn't get my head outa the rut..
Vance
On Jan 25, 2008 7:07 PM, Brian Rosner <[EMAIL PROTECTED]> wrote:
>
> On 2008-01-25 19:18:22 -0700, "Vance Dubberly" <[EMAIL PROTECTED]> said:
>
> >
> > ok so this ones got to be really simple and I've go to be really stupid.
> >
> > I want to update a model of something I already have in the database
> > so I made a ModelForm that doesn't do anything special for it and I
> > use that form to generate a form in a template using the normal
> > form.as_table method. Everything prints out alright except for one
> > thing, there is no id. "Hmm this'll be troublesome.", I think. "How
> > am I gunna know what record to update when the post comes in?" So I
> > figure I'm on crack and obviously don't know anything about http or
> > databases any of that stuff. Maybe django has some magic foo that's
> > over my head. So I print out the form, click the submit button, and
> > now there are two copies of this object in the database. So having
> > read all the docs and book I now come to ya'll. How am i supposed to
> > do a simple update using newforms?
>
> It sounds like you are not passing in the instance to the form in the
> if request.method == "POST" condition. There is no need for an ID in
> the form because you are probably POSTing to the same URL with ID
> there. Check the following code:
>
> def view(request, pk):
> instance = get_object_or_404(MyModel, pk=pk)
> if request.method == "POST":
> form = MyModelForm(request.POST, request.FILES, instance=instance)
> if form.is_valid():
> form.save()
> else:
> form = MyModelForm(instance=instance)
> return render_to_response("mytemplate.html", {
> "form": form,
> }, context_instance=RequestContext(request))
>
> --
> Brian Rosner
> http://oebfare.com
>
>
>
> >
>
--
To pretend, I actually do the thing: I have therefore only pretended to pretend.
- Jacques Derrida
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