Hi folks,
Have come a bit of a cropper with this one:
We're working on an application that is a front-end project manager
for Mercurial source control software.
Most of the application is our own custom views, however one thing
we'd like to keep is using mercurial's own hgweb application to view
repositories.
So for example, mosts URL's such as:
/<projectname>/
/<projectname>/wiki/
/<projectname>/repos/
Will all generate standard views. However when you view a specific repo, i.e:
/<projectname>/repos/<reponame>/
Instead of any custom views, we want to show hgweb:
@check_project_permissions('view_repos')
def repo_detail(request, slug, repo_name):
from mercurial.hgweb.request import wsgiapplication
from mercurial.hgweb.hgwebdir_mod import hgwebdir
def make_web_app():
project = get_object_or_404(Project, name_short__exact=slug)
repo_db = get_object_or_404(Repo, repo_dirname__exact=repo_name)
return hgwebdir(str(settings.MERCURIAL_REPOS +
project.name_short + '/' + repo_db.repo_dirname + '/.hg/hgrc' ))
headers = wsgiapplication(make_web_app)
return HttpResponse(headers)
Now as you can imagine the page is just blank as I'm not actually
passing anything other than the var headers (which is <function
run_wsgi at 0x88c641c>). The problem I am having is HOW to I get the
now-run WSGI app to display as the page in Django?
Any help will be VERY appreciated.
--
Tane Piper
Blog - http://digitalspaghetti.me.uk
Wii: 4734 3486 7149 1830
This email is: [ ] blogable [ x ] ask first [ ] private
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