Using this I could create a static list only. But what I mean is
dynamic list based on database query.
I have the following model for keeping the list of different choices .
class Choice(models.Model):
TYPES = (
('os_type','OS Types'),
('os_type','OS Types'),
)
type = models.CharField(verbose_name='Type', maxlength=30,
choices=TYPES, null=False, blank=False)
value = models.CharField(verbose_name='Key', maxlength=30,
null=False, blank=False)
label = models.CharField(verbose_name='Value', maxlength=30,
null=False, blank=False)
@classmethod
def get_choices_for(self, type):
l=[(k.value,k.label) for k in self.objects.filter(type=type)]
l.extend([('','- select -'),])
l.sort()
return (l)
.... then on the another model I would like to make specific choices
available:
type = models.CharField(verbose_name='OS', maxlength=30, choices =
Choice.get_choices_for('os_type'), null=False, blank=False)
... but using this technique doesnt work as Django runs
Choice.get_choices_for('os_type') only one time when application
starts up ... so it doesnt reflect changes made to Choices table.
David
On Nov 20, 4:57 pm, Michael <[EMAIL PROTECTED]> wrote:
> The following worked for me:
>
> model field:
> type = models.CharField(max_length=10, radio_admin=True,
> choices=CHOICE_LIST)
>
> where CHOICE_LIST is a tuple of tuples, defined inside the model if
> local, outside if you need it in multiple models, like:
> CHOICE_LIST = (('dbasename1', 'displayname1'), ('dbasename2',
> 'displayname2'),)
>
> radio_admin=True causes the list to be displayed as a radio select
> list (instead of a select/drop list or something.) The docs
> athttp://www.djangoproject.com/documentation/model-api/say the
> radio_admin is new in the developmental version.
>
> Hope this helps,
> Michael
>
> On Nov 20, 6:48 am, Christian Joergensen <[EMAIL PROTECTED]> wrote:
>
> > David Marko wrote:
> > > How to define choices for filed that works in admin interface? When I
> > > define CharField as below, the list of choices is computed intially
> > > and doesn't refresh when data changes in Choices table.
>
> > > type = models.CharField(verbose_name='Type', maxlength=30, choices =
> > > Choice.filter("xxxx"), null=False, blank=False)
>
> > Normally, one would use a foreign key in this case:
>
> > choice = models.ForeignKey(Choice)
>
> > Regards,
>
> > --
> > Christian Joergensen | Linux, programming or web
> > consultancyhttp://www.razor.dk| Visit us at:http://www.gmta.info
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