You could do it by having your view act as a proxy. Basically instantiate a new connection to the view in question from your web application using urllib2 or the like. Then get the results, process them as you wish, and send the results of that post-processing (if any) back to the original client request.
-joe On 10/1/07, Greg <[EMAIL PROTECTED]> wrote: > > I was wondering if I could send POST data to another view for > processing. My original view would not be sent any POST data. The > post data would get generated in my view and sent to another view for > processing. > > Is this possible? > > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
