this is question of how list one element of a queryset in template. can somebody help me, thanks!
On 9月20日, 下午2时04分, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote: > i have a templatetags as following: > > {% load bookmarks.templatetags.commrate %} > {% rate_for_object suburb as rate_list %} > {% for rate in rate_list %} > <BR> rate: {{ rate.rate }} > {% endfor %} > it works well for me, but i want to list the element as > {{ rate_list[1].rate }} > but the result is: > > Exception Value: Invalid block tag: 'rate_list[1]' > > how can i list elements out except { % for ...%} > > thanks! --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---