Try iterating through the keys only and get the values from the
dictionary or multi-value dictionary by the keys:
items = # ... your custom dict or request.POST
for k in items:
v = items[k] # should be a string instead of a list with one value
# ... do whatever you want to do with the keys and values
Regards,
Aidas Bendoraitis aka Archatas
On 8/25/07, james_027 <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> Anybody has an idea about this?
>
> Thanks
> james
>
> On Aug 24, 3:27 pm, james_027 <[EMAIL PROTECTED]> wrote:
> > hi,
> >
> > I am using defaultdict to gather organize some data on request.POST.
> > but the result seems to be different when execute outside django ...
> >
> > inside django I could get this result ...
> >
> > {u'item': [u'727'], u'unit_price': [u'5.50'], u'qty': [u'']}
> > {u'item': [u'2'], u'unit_price': [u'23500.00'], u'qty': [u'']}
> > {u'item': [u'1'], u'unit_price': [u'10000.00'], u'qty': [u'']}
> >
> > while outside django I could get this result
> >
> > {u'item': u'727], u'unit_price': u'5.50', u'qty': u''}
> > {u'item': u'2', u'unit_price': u'23500.00', u'qty': u''}
> > {u'item': u'1', u'unit_price': u'10000.00', u'qty': u''}
> >
> > here is my script ...
> >
> > for k, v in request.POST.iteritems():
> > if k.startswith('line'):
> > new_k = k.split('.',1)[0]
> > items[new_k][k.split('.',1)[1]] =
> > v
> > for k, v in items.items():
> > id = 'line%s.' % str(len(fd_list)+1)
> > fd_list.append(InvoiceItemForm(v, auto_id=id+'%s'))
> >
> > the difference makes creating a newform into error
> >
> > Thanks
> > james
>
>
> >
>
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